2x^2(x-1/2)(3x+1/3)=0

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Solution for 2x^2(x-1/2)(3x+1/3)=0 equation: 


x in (-oo:+oo)

2*x^2*(x-(1/2))*(3*x+1/3) = 0

2*x^2*(x-1/2)*(3*x+1/3) = 0

( 2*x^2 )

2*x^2 = 0 // : 2

x^2 = 0

x = 0

( 3*x+1/3 )

3*x+1/3 = 0 // - 1/3

3*x = -1/3 // : 3

x = -1/3/3

x = -1/9

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

x in { 0, -1/9, 1/2 }

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